Java Byte parseByte() Method

by Online Tutorials Library July 22, 2022

Java Byte parseByte() method

The parseByte() method of Java Byte class parses the string argument as a signed decimal. All the characters in the String should be decimal digits, except the first character which can be an ASCII minus or plus sign.

The second parameter parses the specified string argument as a signed byte in the specified radix.

Syntax:

  public static byte parseByte(String s) throws NumberFormatException   public static byte parseByte(String s, int radix) throws NumberFormatException  

Parameters:

The parameters ‘s’ and ‘radix’ represent the string to be parsed and the radix to be used while parsing s.

Throws

The parseByte() method throws:

NumberFormatException– if the string does not contain a parsable byte.

Return Value

This method returns the byte value represented by the argument in decimal.

Example 1

  public class JavaByteParseByteExample1 {      public static void main(String[] args) {          String str=”-8″;          int val=Byte.parseByte(str);          System.out.println(val);      }  }  

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Output:

-8

Example 2

  public class JavaByteParseByteExample2 {      public static void main(String[] args) throws NumberFormatException {          String str=”67″;          //throws an exception if the radix is less than zero          int radix=0;          int val=Byte.parseByte(str,radix);          System.out.println(val);      }  }  

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Output:

Exception in thread "main" java.lang.NumberFormatException: radix 0 less than Character.MIN_RADIX  at java.lang.Integer.parseInt(Integer.java:546)  at java.lang.Byte.parseByte(Byte.java:149)  at com.TutorAspire.JavaByteParseByteExample2.main(JavaByteParseByteExample2.java:8)

Example 3

  public class JavaByteParseByteExample3 {      public static void main(String[] args) throws NumberFormatException {          //the string shout be a byte number          String str=”35″;          int radix=Character.MAX_RADIX;          int val=Byte.parseByte(str,radix);          System.out.println(val);      }  }  

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Output:

Example 4

  public class JavaByteParseByteExample4 {      public static void main(String[] args) throws NumberFormatException {          String str=”null”;          int radix=Character.MAX_RADIX;          System.out.println(radix);          int val=Byte.parseByte(str,radix);          System.out.println(val);      }  }  

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Output:

36  Exception in thread "main" java.lang.NumberFormatException: Value out of range. Value:"null" Radix:36  at java.lang.Byte.parseByte(Byte.java:151)  at com.TutorAspire.JavaByteParseByteExample4.main(JavaByteParseByteExample4.java:8)

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Java Byte parseByte() Method

Java Byte parseByte() method

Syntax:

Parameters:

Throws

Return Value

Example 1

Example 2

Example 3

Example 4

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