Java Float max() method with Examples

by Online Tutorials Library July 22, 2022

Java Float max() Method

The max() method of Java Float class returns the float having greater value between two float values. The returned result is same as by invoking Math.max() method.

Syntax:

Parameters:

Here, a & b are the two operands to be compared.

Return Value:

The max() method returns the greater value between a and b.

Example 1

  import java.util.Scanner;     public class FloatMaxExample1 {      public static void main(String[] args) {          Scanner scanner = new Scanner(System.in);          System.out.println(“Enter first number.”);          Float f1 = scanner.nextFloat();          System.out.println(“Enter second number”);          Float f2 = scanner.nextFloat();         //return the greater of two values          Float f3= Float.max(f1,f2);          System.out.println(“The Max value is: “+f3);      }  }  

Test it Now

Output:

Enter first number.  90.7658  Enter second number  90.84375  The Max value is: 90.84375

Example 2

  import java.util.Scanner;    public class FloatMaxExample2 {      public static void main(String[] args) {          Scanner scanner = new Scanner(System.in);          System.out.println(“Enter total number of elements”);          int n = scanner.nextInt();          // creating array          Float a[] = new Float[n];          System.out.println(“Enter ” + n + ” elements”);          for (int i = 0; i < n; i++) {              a[i] = scanner.nextFloat();          }          Float f3 = 0f;          for (int i = 0; i < n – 1; i++) {           // return the max of n numbers              f3 = Float.max(a[i], a[i + 1]);              f3 = Float.max(a[i], a[i+1]);              a[i+1] = f3;            }             System.out.println(“Maximum value : ” + f3);      }  }  

Test it Now

Output:

Enter total number of elements  4  Enter 4 elements  90.99  90.11  9  8  Maximum value: 90.99

Example 3

  import java.util.Scanner;    public class FloatMaxExample3 {      public static void main(String[] args) {          Scanner scanner = new Scanner(System.in);          System.out.println(“Enter number of elements you want.”);  .l……..        int n = scanner.nextInt();            Float a[] = new Float[n];          System.out.println(“Enter elements”);          for (int i = 0; i < n; i++) {              a[i] = scanner.nextFloat();                      }            Float f1, temp = 0f;          for (int i = 0; i < n ; i++) {              for (int j = i+1; j < n; j++) {                  f1 = Float.max(a[i], a[j]);                  if (a[i].equals(f1)){                      temp = f1;                  a[i] = a[j];                  a[j] = temp;              }              }          }          System.out.print(“Ascending order = “);          for (int i = 0; i < n; i++) {              System.out.print(a[i]+”,”);          }      }  }  

Test it Now

Output:

Enter number of elements you want.  5  Enter elements  90.99  98  123  11  2  Ascending order = 2.0,11.0,90.99,98.0,123.0,

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Java Float max() method with Examples

Java Float max() Method

Syntax:

Parameters:

Return Value:

Example 1

Example 2

Example 3

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