Java Program to Display Even Numbers From 1 to 100

by Online Tutorials Library July 22, 2022

Java Program to Display Even Numbers From 1 to 100

In this section, we will create a Java program to display even numbers from 1 to 100. To learn the Java even number program, you must have the basic knowledge of Java for loop and if statement.

We can use different ways to display even numbers:

Using Java for Loop
Using nested-if Statement
Using while Loop

Using Java for Loop

In the following example, we have declared a variable named number and initialized it with 100 (the limit to print the even number). We have used a for loop that executes up to 100 times and for each iteration of i the if statement checks the number is even or not. After printing each even number, the value if i is increased by 1.

In order to check the number, we have divided the number by 2 if it does not leave any remainder, the number is even and the print statement prints that number.

DisplayEvenNumbersExample1.java

  public class DisplayEvenNumbersExample1  {  public static void main(String args[])   {  int number=100;  System.out.print(“List of even numbers from 1 to “+number+”: “);  for (int i=1; i<=number; i++)   {  //logic to check if the number is even or not  //if i%2 is equal to zero, the number is even  if (i%2==0)   {  System.out.print(i + ” “);  }  }  }  }  

Output:

List of even numbers from 1 to 100: 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50 52 54 56 58 60 62 64 66 68 70 72 74 76 78 80 82 84 86 88 90 92 94 96 98 100

Using nested-if Statement

The following program is slightly different from the above program because we have defined a method that contains the logic to check even number. Inside the method, we have used nested-if statement.

DisplayEvenNumbersExample2.java

  public class DisplayEvennumbersExample2  {  public static void main(String[] args)   {  System.out.println(“List of even numbers: “);       //method calling  displayEvenNumbers(1, 100);   }   //method that checks the number is even or not  private static void displayEvenNumbers(int number, int end)   {   if(number>end)   return;   if(number%2==0)   {   //prints the even numbers  System.out.print(number +” “);   //calling the method and increments the number by 2 if the number is even  displayEvenNumbers(number + 2, end);   }   else   {   //increments the number by 1 if the number is odd  displayEvenNumbers(number + 1, end);   }   }   }  

Output:

List of even numbers:   2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50 52 54 56 58 60 62 64 66 68 70 72 74 76 78 80 82 84 86 88 90 92 94 96 98 100

Using while Loop

In the following program, we have replaced the for loop with while loop.

DisplayEvenNumbersExample3.java

  import java.util.Scanner;  public class DisplayEvenNumbersExample3  {  public static void main(String[] args)   {  int number, i;  Scanner sc=new Scanner(System.in);  System.out.print(“Enter the limit: “);  number = sc.nextInt();  i=2;   System.out.print(“Lit of even numbers: “);  //the while loop executes until the condition become false  while(i<=number)  {  //prints the even number  System.out.print(i +” “);   //increments the variable i by 2  i=i+2;  }  }  }  

Output:

Enter the limit: 100  Lit of even numbers: 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50 52 54 56 58 60 62 64 66 68 70 72 74 76 78 80 82 84 86 88 90 92 94 96 98 100

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