Java program to insert a new node at the middle of the Doubly Linked List

In this program, we create a doubly linked list and insert a new node in the middle of list. If list is empty, both head and tail will point to new node. If list is not empty, then we will calculate the size of the list and divide it by 2 to get the mid-point of the list where new node needs to be inserted.

Consider the above diagram; a new node needs to be added to the middle of the list. First, we calculate the size which in this case is 4. So, to get the mid-point, we divide it by 2 and store it in a variable mid. Node current will point to head. First, we iterate through the list until current points to mid position. Define another node temp which point to node next to current. Insert the new node between current and temp

Algorithm

Define a Node class which represents a node in the list. It will have three properties: data, previous which will point to the previous node and next which will point to the next node.
Define another class for creating the doubly linked list, and it has two nodes: head and tail. Initially, head and tail will point to null.
addNode() will add node to the list:
- It first checks whether the head is null, then it will insert the node as the head.
- Both head and tail will point to a newly added node.
- Head’s previous pointer will point to null and tail’s next pointer will point to null.
- If the head is not null, the new node will be inserted at the end of the list such that new node’s previous pointer will point to tail.
- The new node will become the new tail. Tail’s next pointer will point to null.

a. addInMid() will add a node to the middle of the list:

It first checks whether the head is null (empty list), then it will insert the node as the head.
Both head and tail will point to a newly added node.
If the list is not empty, then we calculate size and divide it by 2 to get the mid-point.
Define node current that will point to head and iterate through the list till current will point to mid node.
Define another node temp which will point to node next to current.
The new node will be inserted after current and before temp such that current will point to the new node and the new node will point to temp.

a. display() will show all the nodes present in the list.

Define a new node ‘current’ that will point to the head.
Print current.data till current points to null.
Current will point to the next node in the list in each iteration.

Program:

  public class InsertMid {        //Represent a node of the doubly linked list        class Node{          int data;          Node previous;          Node next;            public Node(int data) {              this.data = data;          }      }        public int size = 0;      //Represent the head and tail of the doubly linked list      Node head, tail = null;        //addNode() will add a node to the list      public void addNode(int data) {          //Create a new node          Node newNode = new Node(data);            //If list is empty          if(head == null) {              //Both head and tail will point to newNode              head = tail = newNode;              //head’s previous will point to null              head.previous = null;              //tail’s next will point to null, as it is the last node of the list              tail.next = null;          }          else {              //newNode will be added after tail such that tail’s next will point to newNode              tail.next = newNode;              //newNode’s previous will point to tail              newNode.previous = tail;              //newNode will become new tail              tail = newNode;              //As it is last node, tail’s next will point to null              tail.next = null;          }          //Size will count the number of nodes present in the list          size++;      }        //addInMid() will add a node to the middle of the list      public void addInMid(int data) {         //Create a new node          Node newNode = new Node(data);            //If list is empty          if(head == null) {              //Both head and tail will point to newNode              head = tail = newNode;              //head’s previous will point to null              head.previous = null;              //tail’s next point to null, as it is the last node of the list              tail.next = null;          }          else {              //current will point to head              Node current = head, temp = null;                //Store the mid position of the list              int mid = (size % 2 == 0) ? (size/2) : ((size+1)/2);                //Iterate through list till current points to mid position              for(int i = 1; i < mid; i++){                  current = current.next;              }                //Node temp will point to node next to current              temp = current.next;              temp.previous = current;                //newNode will be added between current and temp              current.next = newNode;              newNode.previous = current;              newNode.next = temp;              temp.previous = newNode;          }          size++;      }        //display() will print out the nodes of the list      public void display() {          //Node current will point to head          Node current = head;          if(head == null) {              System.out.println(“List is empty”);              return;          }          while(current != null) {              //Prints each node by incrementing the pointer.                System.out.print(current.data + ” “);              current = current.next;          }          System.out.println();      }        public static void main(String[] args) {            InsertMid dList = new InsertMid();          //Add nodes to the list          dList.addNode(1);          dList.addNode(2);            System.out.println(“Original list: “);          dList.display();            //Adding node ‘3’ in the middle          dList.addInMid(3);          System.out.println( “Updated List: “);          dList.display();            //Adding node ‘4’ in the middle          dList.addInMid(4);          System.out.println(“Updated List: “);          dList.display();            //Adding node ‘5’ in the middle          dList.addInMid(5);          System.out.println(“Updated List: “);          dList.display();      }  }  

Output:

Original list:   1 2   Updated List:   1 3 2   Updated List:   1 3 4 2   Updated List:   1 3 5 4 2

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Java program to insert a new node at the middle of the Doubly Linked List