Java program to print the following pattern on the console 8

by Online Tutorials Library July 22, 2022

Java program to print the following pattern on the console

Algorithm:

STEP 1: START
STEP 2: SET coe=1, rows= 6.
STEP 3: SET i=0. REPEAT STEP 4 to STEP 11 UNTIL i
STEP 4: SET space = 1. REPEAT STEP 5 and STEP 6 UNTIL space<(rows ?i)
STEP 5: PRINT “”
STEP 6: ++space
STEP 7: SET j=0. REPEAT STEP 8 to STEP 9 UNTIL j<=i .
STEP 8: IF(j==0||i==0)
SET coe=1
ELSE
SET coe=coe*(i-j+1) /j
PRINT coe
STEP 9: SET j = j+1
STEP 10: PRINT new line.
STEP 11: SET i=i+1
STEP 12: END

Program:

   class pattern  {      public static void main(String[] args)      {          int coe=1,rows = 6;       for(int i = 0; i < rows; i++) {              for(int space = 1; space < rows – i; ++space) {                  System.out.print(”  “);              }                for(int j = 0; j <= i; j++) {                  if (j == 0 || i == 0)                      coe = 1;                  else                      coe = coe * (i – j + 1) / j;                    System.out.printf(“%4d”, coe);              }        System.out.println();          }      }     }   

Output:

Java program to print the following pattern on the console

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