Program to Insert a New Node at the Middle of the Circular Linked List

Q. Program to insert a new node at the middle of the circular linked list.

Explanation

In this program, we create a circular linked list and insert a new node in the middle of the list. If the list is empty, both head and tail will point to new node. If the list is not empty, then we will calculate the size of the list and divide it by 2 to get the mid-point of the list where the new node needs to be inserted.

Program to insert a new node at the middle of the circular linked list

After inserting the new node in the middle of the list.

Program to insert a new node at the middle of the circular linked list

Consider the above diagram; the new node needs to be added to the middle of the list. First, we calculate the size which in this case is 4. So, to get the mid-point, we divide it by 2 and store it in a variable count. We will define two nodes current, and temp such that temp will point to head, and current will point to the node previous to temp. We iterate through the list till mid-point is reached by incrementing temp to temp.next then, insert the new node in between current and temp. Current’next node will be new and the new’s next node will be temp.

Algorithm

Define a Node class which represents a node in the list. It has two properties data and next which will point to the next node.
Define another class for creating the circular linked list and it has two nodes: head and tail. Variable size stores the size of the list. It has two methods: addInMid() and display() .
addInMid() will add the node to the middle of the list:
1. It first checks whether the head is null (empty list), then it will insert the node as the head.
2. Both head and tail will point to the newly added node.
3. If the list is not empty, then we calculate size and divide it by 2 to get the mid-point.
4. Define node temp that will point to head and current will point to a node previous to temp.
5. Iterate through the list until the middle of the list is reached by incrementing temp to temp.next.
6. The new node will be inserted after current and before temp such that current will point to the new node and the new node will point to temp.
display() will show all the nodes present in the list.
1. Define a new node ‘current’ that will point to the head.
2. Print current.data till current will points to head again.
3. Current will point to the next node in the list in each iteration.

Solution

Python

  #Represents the node of list.  class Node:    def __init__(self,data):      self.data = data;      self.next = None;     class CreateList:      #Declaring head and tail pointer as null.      def __init__(self):        self.head = Node(None);        self.tail = Node(None);        self.head.next = self.tail;        self.tail.next = self.head;        self.size = 0;            #This function will add the new node to the list.      def add(self,data):         newNode = Node(data);         #Checks if the list is empty.         if self.head.data is None:           #If list is empty, both head and tail would point to new node.           self.head = newNode;           self.tail = newNode;           newNode.next = self.head;         else:           #tail will point to new node.           self.tail.next = newNode;           #New node will become new tail.           self.tail = newNode;           #Since, it is circular linked list tail will points to head.           self.tail.next = self.head;         #Size will count the number of element in the list         self.size = self.size+1;            #This function will add the new node at the middle of the list.      def addInMid(self,data):          newNode = Node(data);          #Checks if the list is empty.          if(self.head == None):              #If list is empty, both head and tail would point to new node.              self.head = newNode;              self.tail = newNode;              newNode.next = self.head;          else:              #Store the mid-point of the list              count = (self.size//2) if (self.size % 2 == 0) else ((self.size+1)//2);              #temp will point to head              temp = self.head;              for i in range(0,count):                  #Current will point to node previous to temp.                  current = temp;                  #Traverse through the list till the middle of the list is reached                  temp = temp.next;              #current will point to new node              current.next = newNode;              #new node will point to temp              newNode.next = temp;          self.size = self.size+1;                #Displays all the nodes in the list      def display(self):        current = self.head;        if self.head is None:          print(“List is empty”);          return;        else:            #Prints each node by incrementing pointer.            print(current.data),            while(current.next != self.head):                current = current.next;                print(current.data),           class CircularLinkedList:      cl = CreateList();      #Adds data to the list      cl.add(1);      cl.add(2);      cl.add(3);      cl.add(4);      print(“Original list: “);      cl.display();      #Inserting node ‘5’ in the middle      cl.addInMid(5);      print(“nUpdated List: “);      cl.display();      #Inserting node ‘6’ in the middle      cl.addInMid(6);      print(“nUpdated List: “);      cl.display();  

Output:

Original list:   1 2 3 4  Updated List:   1 2 5 3 4  Updated List:   1 2 5 6 3 4

C

  #include <stdio.h>  #include <string.h>  #include <stdlib.h>     //Represents the node of list.  struct node{      int data;      struct node *next;  };     //Declaring head and tail pointer as null.  struct node *head = NULL;  struct node *tail = NULL;  int size = 0;     //This function will add the new node to the list.  void add(int data){      //Create new node      struct node *newNode = (struct node*)malloc(sizeof(struct node));      newNode->data = data;      //Checks if the list is empty.      if(head == NULL){          //If list is empty, both head and tail would point to new node.          head = newNode;          tail = newNode;          newNode->next = head;      }else {          //tail will point to new node.          tail->next = newNode;          //New node will become new tail.          tail = newNode;          //Since, it is circular linked list tail will point to head.          tail->next = head;      }    size++;  }     //This function will add the new node at the middle of the list.  void addInMid(int data){      int i;      struct node *newNode = (struct node*)malloc(sizeof(struct node));      newNode->data = data;      //Checks if the list is empty.      if(head == NULL){          //If list is empty, both head and tail would point to new node.          head = newNode;          tail = newNode;          newNode->next = head;      }      else{             struct node *temp, *current = NULL;          //Store the mid-point of the list          int count = (size % 2 == 0) ? (size/2) : ((size+1)/2);              //temp will point to head          temp = head;          for(i = 0; i < count; i++){              //Current will point to node previous to temp.              current = temp;              //Traverse through the list till the middle of the list is reached              temp = temp->next;          }          //current will point to new node          current->next = newNode;          //new node will point to temp          newNode->next = temp;     }      size++;  }     //This function will display the nodes of circular linked list  void display(){      struct node *current = head;      if(head == NULL){          printf(“List is empty”);      }      else{           do{            //Prints each node by incrementing pointer.              printf(“%d “, current->data);              current = current->next;          }while(current != head);          printf(“n”);      }  }        int main()  {    //Adds data to the list      add(1);      add(2);      add(3);      add(4);            printf(“Original list:n “);      display();            //Inserting node ‘5’ in the middle      addInMid(5);      printf(“Updated List:n “);      display();            //Inserting node ‘6’ in the middle      addInMid(6);      printf(“Updated List:n “);      display();          return 0;  }  

Output:

Original list:   1 2 3 4  Updated List:   1 2 5 3 4  Updated List:   1 2 5 6 3 4

JAVA

  public class InsertInMid {      //Represents the node of list.          public class Node{              int data;              Node next;              public Node(int data) {                  this.data = data;              }          }                    public int size;          //Declaring head and tail pointer as null.          public Node head = null;          public Node tail = null;                    //This function will add the new node to the list.          public void add(int data){              //Create new node              Node newNode = new Node(data);              //Checks if the list is empty.              if(head == null) {                   //If list is empty, both head and tail would point to new node.                  head = newNode;                  tail = newNode;                  newNode.next = head;              }              else {                  //tail will point to new node.                  tail.next = newNode;                  //New node will become new tail.                  tail = newNode;                  //Since, it is circular linked list tail will points to head.                  tail.next = head;              }              //Size will count the number of element in the list              size++;          }                    //This function will add the new node at the middle of the list.          public void addInMid(int data){              Node newNode = new Node(data);              //Checks if the list is empty.              if(head == null){                  //If list is empty, both head and tail would point to new node.                  head = newNode;                  tail = newNode;                  newNode.next = head;              }              else{                  Node temp,current;                  //Store the mid-point of the list                  int count = (size % 2 == 0) ? (size/2) : ((size+1)/2);                      //temp will point to head                  temp = head;                  current= null;                  for(int i = 0; i < count; i++){                      //Current will point to node previous to temp.                      current = temp;                      //Traverse through the list till the middle of the list is reached                      temp = temp.next;                  }                     //current will point to new node                  current.next = newNode;                  //new node will point to temp                  newNode.next = temp;              }              size++;          }                    //Displays all the nodes in the list          public void display() {              Node current = head;              if(head == null) {                  System.out.println(“List is empty”);              }              else {                   do{                      //Prints each node by incrementing pointer.                      System.out.print(” “+ current.data);                      current = current.next;                  }while(current != head);                  System.out.println();              }          }                    public static void main(String[] args) {              InsertInMid cl = new InsertInMid();              //Adds data to the list              cl.add(1);              cl.add(2);              cl.add(3);              cl.add(4);                            System.out.println(“Original list: “);              cl.display();                            //Inserting node ‘5’ in the middle              cl.addInMid(5);              System.out.println( “Updated List: “);              cl.display();                            //Inserting node ‘6’ in the middle              cl.addInMid(6);              System.out.println(“Updated List: “);              cl.display();          }  }  

Output:

Original list:   1 2 3 4  Updated List:   1 2 5 3 4  Updated List:   1 2 5 6 3 4

C#

  using System;   namespace CircularLinkedList   {                           public class Program      {          //Represents the node of list.          public class Node<T>{              public T data;              public Node<T> next;              public Node(T value) {                  data = value;                  next = null;              }          }                    public class CreateList<T>{              protected Node<T> head = null;                            protected Node<T> tail = null;              int size = 0;                            //This function will add the new node to the list.              public void add(T data){                  //Create new node                  Node<T> newNode = new Node<T>(data);                  //Checks if the list is empty.                  if(head == null){                      head = newNode;                      tail = newNode;                      newNode.next = head;                  }else{                      //tail will point to new node.                      tail.next = newNode;                      //New node will become new tail.                      tail = newNode;                      //Since, it is circular linked list tail will points to head.                      tail.next = head;                  }                  size++;              }                            //This function will add the new node at the middle of the list.              public void addInMid(T data){                  Node<T> newNode = new Node<T>(data);                  //Checks if the list is empty.                  if(head == null){                      //If list is empty, both head and tail would point to new node.                      head = newNode;                      tail = newNode;                      newNode.next = head;                  }                  else{                      Node<T> temp,current;                      //Store the mid-point of the list                      int count = (size % 2 == 0) ? (size/2) : ((size+1)/2);                          //temp will point to head                      temp = head;                      current= null;                      for(int i = 0; i < count; i++){                          //Current will point to node previous to temp.                          current = temp;                          //Traverse through the list till the middle of the list is reached                          temp = temp.next;                      }                            //current will point to new node                      current.next = newNode;                      //new node will point to temp                      newNode.next = temp;                  }                  size++;                 }                            //Displays all the nodes in the list              public void display(){                  Node<T> current = head;                  if(head == null){                      Console.WriteLine(“List is empty”);                  }                  else{                      do{                          //Prints each node by incrementing pointer.                          Console.Write(” “+ current.data);                          current = current.next;                      }while(current != head);                  }                  }          }                    public static void Main()          {                        CreateList<int> cl = new CreateList<int>();              //Adds data to the list              cl.add(1);              cl.add(2);              cl.add(3);              cl.add(4);                            Console.WriteLine(“Original list: “);              cl.display();                            //Inserting node ‘5’ in the middle              cl.addInMid(5);              Console.WriteLine();              Console.WriteLine(“Updated List: “);              cl.display();                            //Inserting node ‘6’ in the middle              cl.addInMid(6);              Console.WriteLine();              Console.WriteLine(“Updated List: “);              cl.display();          }      }  }  

Output:

Original list:   1 2 3 4  Updated List:   1 2 5 3 4  Updated List:   1 2 5 6 3 4

PHP

  <!DOCTYPE html>  <html>  <body>  <?php  //Represents the node of list.  class Node{      public $data;      public $next;      function __construct($data){          $this->data = $data;          $this->next = NULL;      }  }  class CreateList{      //Declaring head and tail pointer as null.      private $head;      private $tail;      private $size;      function __construct(){          $this->head = NULL;          $this->tail = NULL;          $this->size = 0;      }            //This function will add the new node to the list.      function add($data){          //Create new node          $newNode = new Node($data);          //Checks if the list is empty.          if($this->head == NULL){              //If list is empty, both head and tail would point to new node.              $this->head = $newNode;              $this->tail = $newNode;              $newNode->next = $this->head;          }          else{              //tail will point to new node.              $this->tail->next = $newNode;              //New node will become new tail.              $this->tail = $newNode;              //Since, it is circular linked list tail will point to head.              $this->tail->next = $this->head;          }          $this->size++;      }            //This function will add the new node at the middle of the list.      function addInMid($data){          $newNode = new Node($data);          //Checks if the list is empty.          if($this->head == NULL){              //If list is empty, both head and tail would point to new node.              $this->head = $newNode;              $this->tail = $newNode;              $newNode->next = $this->head;          }          else{              //Store the mid-point of the list              $count = ($this->size % 2 == 0) ? ($this->size/2):(($this->size+1)/2);                  //temp will point to head              $temp = $this->head;              for($i = 0; $i < $count; $i++){                  //Current will point to node previous to temp.                  $current = $temp;                  //Traverse through the list till the middle of the list is reached                  $temp = $temp->next;              }                 //$current will point to new node              $current->next = $newNode;              //new node will point to temp              $newNode->next = $temp;          }          $this->size++;      }            //Displays all the nodes in the list      function display() {          $current = $this->head;          if($this->head == NULL) {              echo “List is empty”;          }          else {               do{                  echo(” $current->data”);                  $current = $current->next;              }while($current != $this->head);              echo “<br>”;          }      }     }  $cl = new CreateList();  //Adds data to the list  $cl->add(1);  $cl->add(2);  $cl->add(3);  $cl->add(4);  echo “Original list: <br>”;  $cl->display();  //Inserting node ‘5’ in the middle  $cl->addInMid(5);  echo “Updated List: <br>”;  $cl->display();  //Inserting node ‘6’ in the middle  $cl->addInMid(6);  echo “Updated List: <br>”;  $cl->display();  ?>  </body>  </html>  

Output:

Original list:   1 2 3 4  Updated List:   1 2 5 3 4  Updated List:   1 2 5 6 3 4

Next Topic#

Q. Program to insert a new node at the middle of the circular linked list.

Explanation

Algorithm

Solution

Python

C

JAVA

C#

PHP

Wind Energy

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