Java Double max() Method with Examples

by Online Tutorials Library July 22, 2022

Java Double max() Method

The max() method of Java Double class returns the double object having greater value amongst two double values. The result returned is same as by invoking Math.max() method.

Syntax

Parameters

Here, a & b are the two operands to be compared

Return value

The max() method returns the greater value amongst a and b.

Example 1

  import java.util.Scanner;    public class Double_maxMethodExample1 {      public static void main(String[] args) {          Scanner scanner = new Scanner(System.in);          System.out.println(“Enter first number.”);          Double d1 = scanner.nextDouble();          System.out.println(“Enter second number”);          Double d2 = scanner.nextDouble();          // return the greater of two values          Double d3= Double.max(d1,d2);          System.out.println(“Enter third number”);          Double d4 =scanner.nextDouble();          Double d5 =Double.max(d3,d4);          System.out.println(“The Max value is: “+d5);      }  }  

Test it Now

Output:

Enter first number.  67  Enter second number  89.001  Enter third number  89.0011  The Max value is: 89.0011

Example 2

  import java.util.Scanner;    public class Double_maxMethodExample2 {      public static void main(String[] args) {  Scanner scanner = new Scanner(System.in);          System.out.println(“Enter total number of elements”);          int n = scanner.nextInt();          // creating array          Double a[] = new Double[n];          System.out.println(“Enter ” + n + ” elements”);          for (int i = 0; i < n; i++) {              a[i] = scanner.nextDouble();          }          Double d1 = 0.0;          for (int i = 0; i < n – 1; i++) {              // return the max of n numbers              d1 = Double.max(a[i], a[i+1]);              a[i+1] = d1;                  //System.out.println(d1);          }          System.out.println(“Maximum value : ” + d1);        }        }  

Test it Now

Output:

Enter total number of elements  5  Enter 5 elements  90.009  98.887  67.8898  7566  77  Maximum value : 7566.0

Example 3

  import java.util.Scanner;    public class Double_maxMethodExample3 {      public static void main(String[] args) {          Scanner scanner = new Scanner(System.in);          System.out.println(“Enter number of elements you want.”);          int n = scanner.nextInt();            Double a[] = new Double[n];          System.out.println(“Enter elements”);          for (int i = 0; i < n; i++) {              a[i] = scanner.nextDouble();          }          Double f1, temp = 0.0;          for (int i = 0; i < n ; i++) {              for (int j = i+1; j < n; j++) {                  f1 = Double.max(a[i], a[j]);                  if (a[i].equals(f1)){                      //temp = f1;                      a[i] = a[j];                      a[j] = f1;                  }              }          }          System.out.print(“Descending order = “);          for (int i = n-1; i >=0; i–) {              System.out.print(a[i]+”,”);          }      }  }  

Test it Now

Output:

Enter number of elements you want.  5  Enter elements  90.009  90.00008  90  89  89.999  Descending order = 90.009,90.00008,90.0,89.999,89.0,

Next TopicJava Double

byteValue()compare compareTo()double doubleValue()floatValue()intValue()isNaN()java longBitsToDouble()longValue()parseDouble()shortValue()toHexString()toString()valueOf()

Java Double max() Method with Examples

Java Double max() Method

Syntax

Parameters

Return value

Example 1

Example 2

Example 3

Java Collections sort() Method with Examples

Java Float isFinite() method with Examples

You may also like