Java Double min() Method with Examples

by Online Tutorials Library July 22, 2022

Java Double min() Method

The min() method of Java Double class returns the double having minor value amongst two double values. The result returned is same as by invoking Math.min () method.

Syntax

Parameters

Here, a & b are the two operands to be compared.

Return value

The min() method returns the lesser value amongst a and b.

Example 1

  import java.util.Scanner;    public class Double_minMethodExample1 {          public static void main(String[] args) {              Scanner scanner = new Scanner(System.in);              System.out.println(“Enter first number.”);              Double d1 = scanner.nextDouble();              System.out.println(“Enter second number”);              Double d2 = scanner.nextDouble();              //return the smaller of two values              Double d3= Double.min(d1,d2);              System.out.println(“Enter third number”);              Double d4 = scanner.nextDouble();              Double d5= Double.min(d3,d4);              System.out.println(“The smaller number is: “+d5);          }      }  

Test it Now

Output:

Enter first number.  67.90  Enter second number  67.89  Enter third number  67.99999  The smaller number is: 67.89

Example 2

  import java.util.Scanner;        public class Double_minMethodExample2 {          public static void main(String[] args) {              Scanner scanner = new Scanner(System.in);              System.out.println(“Enter total number of elements”);              int n = scanner.nextInt();              // creating array              Double a[] = new Double[n];              System.out.println(“Enter ” + n + ” elements”);              for (int i = 0; i < n; i++) {                  a[i] = scanner.nextDouble();              }              Double d1 = 0.0;              Double d2 =0.0;              for (int i = 0; i < n – 1; i++) {                  // return the maximum value of n numbers                  d1 = Double.max(a[i], a[i + 1]);                  a[i+1] = d1;              }              System.out.println(“Maximum value : ” + d1);              for (int i = 0; i < n – 1; i++) {                  // return the minimum value of n numbers                  d2 = Double.min(a[i], a[i+1]);                  a[i+1] = d2;              }              System.out.println(“Minimum value : “+d2);          }      }  

Test it Now

Output:

Enter total number of elements  4  Enter 4 elements  100.098  100.9876  19635  100  Maximum value : 19635.0  Minimum value : 100.098

Example 3

  import java.util.Scanner;    public class Double_minMethodExample3 {         public static void main(String[] args) {              Scanner scanner = new Scanner(System.in);              System.out.println(“Enter number of elements you want.”);              int n = scanner.nextInt();                Double a[] = new Double[n];              System.out.println(“Enter elements”);              for (int i = 0; i < n; i++) {                  a[i] = scanner.nextDouble();              }              Double d1, temp = 0.0;              for (int i = 0; i < n ; i++) {                  for (int j = i+1; j < n; j++) {                      d1 = Double.min(a[i], a[j]);                      if (a[i].equals(d1)){                          temp = d1;                          a[i] = a[j];                          a[j] = temp;                      }                  }              }              System.out.print(“Descending order = “);              for (int i = 0; i < n; i++) {                  System.out.print(a[i]+”>”);              }          }      }  

Test it Now

Output:

Enter number of elements you want.  4  Enter elements  10.000  10,001  11  12  Descending order = 10001.0>12.0>11.0>10.0>

Example 4

  public class Double_minMethodExample4 {         public static void main(String[] args) {              Double d1=Double.MIN_VALUE;              System.out.println(“Min_Value = “+d1);              Double d2=Double.MIN_NORMAL;              System.out.println(“Min_Value = “+d2);              Double d3=Double.min(d1,d2);              System.out.println(“1. Smaller value = “+d3);              System.out.println();                Double d7=Double.POSITIVE_INFINITY;              System.out.println(“POSITIVE_INFINITY = “+d7);              Double d8=Double.NEGATIVE_INFINITY;              System.out.println(“NEGATIVE_INFINITY = “+d8);              Double d9 =Double.min(d7,d8);              System.out.println(“2. Smaller value = “+d9);          }      }    

Test it Now

Output:

Min_Value = 4.9E-324  Min_Value = 2.2250738585072014E-308  1. Smaller value = 4.9E-324    POSITIVE_INFINITY = Infinity  NEGATIVE_INFINITY = -Infinity  2. Smaller value = -Infinity

Next TopicJava Double

byteValue()compare compareTo()double doubleValue()floatValue()intValue()isNaN()java longBitsToDouble()longValue()parseDouble()shortValue()toHexString()toString()valueOf()

Java Double min() Method with Examples

Java Double min() Method

Syntax

Parameters

Return value

Example 1

Example 2

Example 3

Example 4

Java Collections sort() Method with Examples

Java Float isFinite() method with Examples

You may also like