Program To Print Pattern 3

by Online Tutorials Library July 22, 2022

Write a program to print the following pattern.

*000*000*

0*00*00*0

00*0*0*00

000***000

Algorithm

STEP 1: START
STEP 2: SET lines=4
STEP 3: Initialize i and j
STEP 4: SET i =1
STEP 5: REPEAT STEP 6 to 15 UNTIL i less than or equals to line
STEP 6: SET j=1
STEP 7: REPET STEP 8 and 9 UNTIL j is less than or equals to lines
STEP 8: IF i is equal to j PRINT * ELSE PRINT 0
STEP 9: SET j = j + 1
STEP 10: DECREMENT j by 1 and PRINT *
STEP 11: REPEAT STEP 12 and 13 UNTIL j is greater than 0
STEP 12: IF i is equals to j PRINT * ELSE PRINT 0
STEP 13: SET j = j – 1
STEP 14: PRINT a new line
STEP 15: SET i = i + 1
STEP 16: EXIT

Solution:

C Program:

  #include <stdio.h>  int main()  {    int lines=4;    int i,j;    for(i=1;i<=lines;i++){// this loop is used to print lines        for(j=1;j<=lines;j++){// this loop is used to print * in a line            if(i==j)              printf(“*”);              else            printf(“0”);        }        j–;        printf(“*”);        while(j>=1){// this loop is used to print * in a line            if(i==j)            printf(“*”);            else            printf(“0”);            j–;        }      printf(“n”);    }      return 0;  }  

Output:

*000*000*  0*00*00*0  00*0*0*00  000***000

Java Program:

  public class pattern{       public static void main(String[] args){      int lines=4;      int i,j;      for(i=1;i<=lines;i++){// this loop is used to print lines        for(j=1;j<=lines;j++){// this loop is used to print * in a line            if(i==j)               System.out.print(“*”);              else             System.out.print(“0”);        }        j–;         System.out.print(“*”);        while(j>=1){// this loop is used to print * in a line            if(i==j)             System.out.print(“*”);            else             System.out.print(“0”);            j–;        }      System.out.println(“”);    }           }  }  

Output:

*000*000*  0*00*00*0  00*0*0*00  000***000

C# Program:

  using System;    public class Program  {  public static void Main()  {  int lines=4;    int i,j;    for(i=1;i<=lines;i++){// this loop is used to print lines        for(j=1;j<=lines;j++){// this loop is used to print lines            if(i==j)              Console.Write(“*”);              else            Console.Write(“0”);        }        j–;        Console.Write(“*”);        while(j>=1){// this loop is used to print lines            if(i==j)            Console.Write(“*”);            else            Console.Write(“0”);            j–;        }      Console.WriteLine(“”);    }  }  }  

Output:

*000*000*  0*00*00*0  00*0*0*00  000***000

PHP Program:

  <?php  $lines=4;  $i;  $j;    for($i=1;$i<=$lines;$i++){// this loop is used to print lines        for($j=1;$j<=$lines;$j++){ // this loop is used to print lines            if($i==$j)              echo “*”;              else            echo “0”;        }        $j–;        echo “*”;        while($j>=1){// this loop is used to print lines            if($i==$j)            echo “*”;            else            echo “0”;            $j–;        }      echo “<br>”;    }  ?>  

Output:

*000*000*  0*00*00*0  00*0*0*00  000***000

Python Program:

  lines=4  i=1  j=1  while i<=lines:#this loop is used to print lines      j=1      while j<=lines:#this loop is used to print lines          if i==j:              print(“*”, end=”, flush=True)          else :              print(“0″, end=”, flush=True)          j=j+1      j=j-1;      print(“*”, end=”, flush=True)      while j>=1:#this loop is used to print lines          if i==j:              print(“*”, end=”, flush=True)          else :              print(“0″, end=”, flush=True)          j=j-1      print(“”);      i=i+1  

Output:

*000*000*  0*00*00*0  00*0*0*00  000***000

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Program To Print Pattern 3

Write a program to print the following pattern.

Algorithm

Solution:

C Program:

Java Program:

C# Program:

PHP Program:

Python Program:

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